2x^2-49x+10x+70=0

Solution for 2x^2-49x+10x+70=0 equation:

2x^2-49x+10x+70=0

We add all the numbers together, and all the variables

2x^2-39x+70=0

a = 2; b = -39; c = +70;
Δ = b2-4ac
Δ = -392-4·2·70
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-39)-31}{2*2}=\frac{8}{4}
=2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-39)+31}{2*2}=\frac{70}{4}
=17+1/2
$